[6(2y-3)=42

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Solution for [6(2y-3)=42 equation: 



6(2y-3)=42

We move all terms to the left:

6(2y-3)-(42)=0

We multiply parentheses

12y-18-42=0

We add all the numbers together, and all the variables

12y-60=0

We move all terms containing y to the left, all other terms to the right

12y=60

y=60/12

y=5

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